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\(1+1+1+1+1+1+1+....+1\)
\(=1.10000\)
\(=10000\)
\(2+2+2+2+2+2+2+....+2\)
\(=2.10000\)
\(=20000\)
\(0+1+2+3+4+5+6+7+8+9+.....+10000\)
Số số hạng của dãy là:
(10000-0):1+1=10001( số )
Tổng của dãy là:
(10000+0).10001:2=50005000
![](https://rs.olm.vn/images/avt/0.png?1311)
a) không tính đươc vì ko có kết quả của 1:0
b) 22
nhớ tkkkkkkkkkkkk
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\(a)\) \(S=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+...+\frac{1}{2187}\)
\(S=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^7}\)
\(3S=3+1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^6}\)
\(3S-S=\left(3+1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^6}\right)-\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^7}\right)\)
\(2S=3+\frac{1}{3^7}\)
\(2S=\frac{3^8+1}{3^7}\)
\(S=\frac{3^8+1}{3^7}.\frac{1}{2}\)
\(S=\frac{3^8+1}{2.3^7}\)
Vậy \(S=\frac{3^8+1}{2.3^7}\)
Chúc bạn học tốt ~
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C=1/(2x4)+1/(4x6)+...+1/(18x20)
2C=2/(2x4)+2/(4x6)+...+2/(18x20)
2C=1/2-1/4+1/4-1/6+....-1/20
2C= 1/2- 1/20
2C= 9/20
C= 9/20 x 1/2
C= 9/40
- Quên k auto súc vặc
![](https://rs.olm.vn/images/avt/0.png?1311)
C = 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5
C = 1/1 - 1/5
C = 4/5
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(B=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}\)
\(\Rightarrow B=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\)
\(\Rightarrow3B=1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}\)
\(\Rightarrow3B-B=\left(1+\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^4}+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}+\frac{1}{3^5}+\frac{1}{3^6}\right)\)
\(\Rightarrow2B=1-\frac{1}{3^6}\)
\(\Rightarrow B=\frac{1-\frac{1}{3^6}}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{5}{6}+\frac{1}{6}=1.\)
\(b,\frac{1}{2}-\frac{1}{3}-\frac{1}{6}=\frac{1}{6}-\frac{1}{6}=0.\)
\(c,\frac{1}{2}x\frac{2}{3}x\frac{3}{4}=\frac{1}{3}x\frac{3}{4}=\frac{1}{4}.\)
\(d,\frac{1}{2}:\frac{2}{3}:\frac{3}{4}=\frac{3}{4}:\frac{3}{4}=1.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3}{6}+\frac{2}{6}+\frac{1}{6}=1\)
b) \(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}=\frac{3}{6}-\frac{2}{6}-\frac{1}{6}=0\)
c) \(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}=\frac{1}{4}\)
d) \(\frac{1}{2}:\frac{2}{3}:\frac{3}{4}=\frac{1}{2}.\frac{3}{2}.\frac{4}{3}=1\)
Chú ý : Dấu \(.\)là dấu x nha
![](https://rs.olm.vn/images/avt/0.png?1311)
câu 1:
\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}\)
\(\hept{\begin{cases}15=3\cdot5\\35=5\cdot7\end{cases}}\\ \hept{\begin{cases}3=3\\63=3^2\cdot7\\99=3^2\cdot11\end{cases}}\)
=>\(\frac{2310}{3465}+\frac{462}{3465}+\frac{198}{3465}+\frac{110}{3465}+\frac{70}{3465}\)
=>\(\frac{2310+462+198+110+70}{3465}\)
=>\(\frac{3150}{3465}\)=\(\frac{10}{11}\)
Why? B giải thik mik nghe coi chứ mik hem hỉu