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\(a,\left(36+79\right)+\left(145-79-36\right)\)
\(=36-36+79-79+145\)
\(=145\)
6)(36+79)+(145-79-36)
= 36+79+145-79-36
= (36-36)+(79-79)+145
=145
7)3.10-[12-(-9-1)]
=30-(12-9+1)
=30-12+9-1
=26
8)45-5.(12+9)
=45-60-45
=(45-45)-60
=0-60
=-60
9)24.(16-5)-16.(24-5)
=24.16-14.5-16.24+16.5
=16.5-14.5
=5(16-14)
=5.2
=10
10)-23.63+23.21-58.23
= 23(-63+21-58)
=23.-100
=-2300
11)[(-851)+5924]+[(-5924)+851]
=-851+5924-5924+851
=(-851+851)+(5924-5924)
=0+0
=0
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-5/9 - ( -5/12 ) =-5/9+5/12=-20/36+15/36=-5/36
-1/16 - 1/15=-15/240-16/240=-31/240
11/36 - ( -7/24 )=11/36+7/24=22/72+21/72 =43/72
\(-\frac{5}{9}-\left(-\frac{5}{12}\right)=-\frac{60}{108}-\left(-\frac{45}{108}\right)=-\frac{15}{108}=-\frac{5}{36}.\)
\(\frac{-1}{6}-\frac{1}{15}=\frac{-5}{30}-\frac{2}{30}=\frac{-7}{30}\)
\(\frac{11}{36}-\left(-\frac{7}{24}\right)=\frac{22}{72}-\left(-\frac{21}{72}\right)=\frac{43}{72}\)
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a 11/36 - ( -7 )/24
= 11/36 + 7/24
= 22/72 + 21/72
= 43/72
-5/9 - -5/12
= -5/9 + 5/12
= -20/36 + 15/36
= -5/36
\(\frac{11}{36}-\frac{-7}{24}=\frac{11}{36}+\frac{7}{24}=\frac{22}{72}+\frac{21}{72}=\frac{43}{72}\)
\(-\frac{5}{9}-\frac{-5}{12}=-\frac{5}{9}+\frac{5}{12}=-\frac{20}{36}+\frac{15}{36}=-\frac{5}{36}\)
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`#` `\text{dkhanhqlv}`
`a)1/8-1/2`
`=1/8-4/8`
`=-3/8`
`b)-11/12-(-1)`
`=-11/12+1`
`=-11/12+12/12`
`=1/12`
`c)3/5-5/6`
`=18/30-25/30`
`=-7/30`
`d)-1/16-1/15`
`=-15/240-16/240`
`=-31/240`
`e)11/36-(-7/24)`
`=11/36+7/24`
`=22/72+21/72`
`=43/72`
`g)-5/9-(-5/12)`
`=-5/9+5/12`
`=-20/36+15/36`
`=-5/36`
a) \(\dfrac{1}{8}-\dfrac{1}{2}=\dfrac{1}{8}-\dfrac{4}{8}=-\dfrac{3}{8}\)
b) \(-\dfrac{11}{12}-\left(-1\right)=-\dfrac{11}{12}+\dfrac{12}{12}=\dfrac{1}{12}\)
c) \(\dfrac{3}{5}-\dfrac{5}{6}=\dfrac{18}{30}-\dfrac{25}{30}=-\dfrac{7}{30}\)
d) \(-\dfrac{1}{16}-\dfrac{1}{15}=-\dfrac{15}{240}-\dfrac{16}{240}=-\dfrac{31}{240}\)
e) \(\dfrac{11}{36}-\left(-\dfrac{7}{24}\right)=\dfrac{11}{36}+\dfrac{7}{24}=\dfrac{22}{72}+\dfrac{21}{72}=\dfrac{43}{72}\)
g) \(-\dfrac{5}{9}-\left(-\dfrac{5}{12}\right)=-\dfrac{5}{9}+\dfrac{5}{12}=-\dfrac{20}{36}+\dfrac{15}{36}=-\dfrac{5}{36}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\left(\dfrac{7}{20}+\dfrac{11}{15}-\dfrac{15}{12}\right):\left(\dfrac{11}{20}-\dfrac{26}{45}\right).\)
\(=\left(\dfrac{21}{60}+\dfrac{44}{60}-\dfrac{75}{60}\right):\left(\dfrac{99}{180}-\dfrac{104}{180}\right).\)
\(=\left(\dfrac{65}{60}-\dfrac{75}{60}\right):\left(-\dfrac{5}{180}\right).\)
\(=-\dfrac{10}{60}:\left(-\dfrac{5}{180}\right).\)
\(=-\dfrac{1}{6}:\left(-\dfrac{1}{36}\right).\)
\(=-\dfrac{1}{6}.\left(-36\right).\)
\(=\dfrac{-1.\left(-36\right)}{6}=\dfrac{36}{6}=6.\)
Vậy......
\(b,\dfrac{5-\dfrac{5}{3}+\dfrac{5}{9}-\dfrac{5}{27}}{8-\dfrac{8}{3}+\dfrac{8}{9}-\dfrac{8}{27}}:\dfrac{15-\dfrac{15}{11}+\dfrac{15}{121}}{16-\dfrac{16}{11}+\dfrac{16}{121}}.\)
\(=\dfrac{5\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}{8\left(1-\dfrac{1}{3}+\dfrac{1}{9}-\dfrac{1}{27}\right)}:\dfrac{15\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}{16\left(1-\dfrac{1}{11}+\dfrac{1}{121}\right)}.\)
\(=\dfrac{5}{8}:\dfrac{15}{16}.\)
\(=\dfrac{5}{8}.\dfrac{16}{15}=\dfrac{5.16}{8.15}=\dfrac{1.2}{1.3}=\dfrac{2}{3}.\)
Vậy......
c, (làm tương tự câu b).
~ Học tốt!!! ~
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1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
-1/16-1/5= -1/5
11/36- - 7/24= 1/2
-5/9- - 5/12= -1/10
chúc mày học dốt:)))