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\(2\left(x-5\right)+10=20\)
\(\Leftrightarrow2\left(x-5\right)=10\)
\(\Leftrightarrow x-5=5\)
\(\Leftrightarrow x=10\)
\(\left(3x+1\right)-17=5\)
\(\Leftrightarrow3x+1=22\)
\(\Leftrightarrow3x=21\)
\(\Leftrightarrow x=7\)
\(\left(10x+120\right)-138=262\)
\(\Leftrightarrow10x+120=400\)
\(\Leftrightarrow10x=280\)
\(\Leftrightarrow x=28\)
\(4\left(x+1\right)-12=8\)
\(\Leftrightarrow4\left(x+1\right)=20\)
\(\Leftrightarrow x+1=5\)
\(\Leftrightarrow x=4\)
\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)
\(\Leftrightarrow2x+\frac{7}{3}=\frac{1}{3}\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-1\)
\(2\left(x-5\right)+10=20\)
\(2x-10+10=20\)
\(2x=20\)
\(x=10\)
\(\left(3x+1\right)-17=5\)
\(3x+1-17=5\)
\(3x-16=5\)
\(3x=21\)
\(x=\frac{21}{3}=7\)
\(\left(10x+120\right)-138=262\)
\(10x+120-138=262\)
\(10x-18=262\)
\(10x=280\)
\(x=28\)
\(4\left(x+1\right)-12=8\)
\(4x+4-12=8\)
\(4x-8=8\)
\(4x=16\)
\(x=4\)
2.(x-5)+10 = 20
2.(x-5) = 20 - 10
2.(x-5) = 10
x-5 = 10 : 2
x-5 = 5
x = 5 + 5
x = 10
(3x+1)-17 = 5
3x+1 = 5 + 17
3x+1 = 22
3x = 22 - 1
3x = 21
x = 21 : 3
x = 7
(10x+120)-138 = 262
10x+120 = 262 + 138
10x+120 = 400
10x = 400-120
10x = 280
x = 280 : 10
x = 28
4.(x+1)-12 = 8
4.(x+1) = 8 + 12
4.(x+1) = 20
x+1 = 20 : 4
x+1 = 5
x = 5 - 1
x = 4
\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)
\(2x+\frac{7}{3}=\frac{1}{3}\)
\(2x=\frac{1}{3}-\frac{7}{3}\)
\(2x=-2\)
x = (-2) : 2
x = -1
ta chỉ cần lấy 10x12=120
10x hiểu là 10x?
chỉ chia là ra
tìm x
a) (3x + 5) + (2x + 10) =100
=> (3x + 2x) + ( 5 + 10 ) = 100
=> 5x + 15 =100
=> 5x = 100-15
=> 5x = 85
=> x =85:5
=> x = 17
b) 10x - 24-8x=56
=> (10x - 8x) -24 = 56
=> 2x - 24 = 56
=> 2x = 56 - 24
=> 2x = 32
=> x = 32 : 2
=> x = 16
c) 2(x+1)+(x+4) =120
=> 2.5x = 120
=> 5x = 120 : 2
=> 5x = 60
=> x = 60:5
=> x = 12
có gì sai sót mong em thông cảm !!!
Anh giải theo lập phương trình, mong e thông cảm. Giờ a giải cách lớp 6 cho nhé:
1.
10x -24- 8x= 56
(10x-8x) -24= 56
2x -24= 56
2x= 56- 24
2x= 32
x= 32/2
x=16
\(a,2x-138=2^3-3^2\)
\(2x-138=8-9\)
\(2x-138=-1\)
\(2x=-1+138\)
\(2x=137\)
\(x=137:2\)
\(x=68,5\)
\(Vậyx=68,5\)
\(b,\left[3.\left(x+2\right):7\right].4=120\)
\(3x+6:7=120:4\)
\(3x+\frac{6}{7}=30\)
\(3x=30-\frac{6}{7}\)
\(3x=\frac{204}{7}\)
\(x=\frac{204}{7}:3\)
\(x=\frac{204}{7}.\frac{1}{3}\)
\(x=\frac{68}{7}\)
\(Vậyx=\frac{68}{7}\)
\(c,\left\{\left[\left(2x+14\right):2^2-3\right]:2\right\}-1=0\)
\(\left\{\left[\left(2x+14\right):4-3\right]:2\right\}=0+1\)
\(\left[\left(2x+14\right):4-3\right]:2=1\)
\(\left(2x+14\right):4-3=1.2\)
\(\left(2x+14\right):4-3=2\)
\(\left(2x+14\right):4=2+3\)
\(\left(2x+14\right):4=5\)
\(2x+14=5.4\)
\(2x+14=20\)
\(2x=20-14\)
\(2x=6\)
\(\Rightarrow x=6:2\)
\(x=3\)
\(Vậyx=3\)
(10x + 120) - 138 = 262
10x+120=262+138
10x+120=400
10x=400-120
10x=280
x=280:10
x=28