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b,
\(1.2.3...9-1.2.3...8-1.2.3....7.8^2\\ =1.2.3....8\left(9-1-8\right)\\ =1.2.3....8.0\\ =0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(=\left(100+121+144\right):\left(169+196\right)\)
\(=\frac{365}{365}=1\)
(102 + 112 + 122) : (132 + 142)
= (100 + 121 + 144) : (169 + 196)
= 365 : 365
= 1
Ủng hộ mk nha ^_-
![](https://rs.olm.vn/images/avt/0.png?1311)
a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
![](https://rs.olm.vn/images/avt/0.png?1311)
(102 +112+122):(132 +142)
=(100+121+144):(169+196)
=365:365
=1
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(=\left(100+121+144\right):\left(169+196\right)\)
\(=\left(221+144\right):365\)
\(=365:365\)
\(=1\)Vậy kết quả = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
|x-10|+|x-11|+|x-12|+|x-13|=4
=>|x-10|+|x-13|+|x-11|+|x-12|=4
=>|x-10|+|13-x|+|x-11|+|12-x|=4
Ta có: |x-10|+|x-13|+|x-11|+|x-12|>=3+1=4(Bất đẳng thức giá trị tuyệt đối)
DBXRK 11<=x<=12=>x=11 hoặc x=12
Vậy x=11 hoặc x=12
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{121.75.130.169}{39.60.11.198}=\dfrac{11.11.25.3.13.10.169}{13.3.6.10.11.11.18}=\dfrac{25.169}{6.18}\)