Câu hỏi của sdfgyuhji

Question

1 +x)+(3+x)+(5+x) + ………..+ (99 + x) =4950

Yen Nhi · Accepted Answer

$\left(1+x\right)+\left(3+x\right)+\left(5+x\right)+...+\left(99+x\right)=4950$

$\Rightarrow1+x+3+x+5+x+...+99+x=4950$

$\Rightarrow\left(1+3+5+...+99\right)+\left(x+x+...+x\right)=4950$

$\Rightarrow2500+50x=4950$

$\Rightarrow50x=2450$

$\Rightarrow x=49$

Câu trả lời:

$\left(1+x\right)+\left(3+x\right)+\left(5+x\right)+...+\left(99+x\right)=4950$

$\Rightarrow1+x+3+x+5+x+...+99+x=4950$

$\Rightarrow\left(1+3+5+...+99\right)+\left(x+x+...+x\right)=4950$

$\Rightarrow2500+50x=4950$

$\Rightarrow50x=2450$

$\Rightarrow x=49$