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\(1\frac{13}{15}\) . 0,75 - ( 11/20 +25% ) :3/7
=\(\frac{28}{15}\) . 3/4 - ( 11/20 +25/100 ) :3/7
=28/15. 3/4- 4/5 : 3/7
=7/5 - 28/15
=-7/15
Thấy đúng thì bấm đúng cho mh nha!!!
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)
= \(\frac{7}{5}-\frac{4}{5}:\frac{3}{7}\)
= \(\frac{7}{5}-\frac{28}{15}\)
= \(-\frac{7}{15}\)
\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)
=>\(\frac{28}{15}\cdot\frac{3}{4}-\left(\frac{55}{100}+\frac{25}{100}\right)\cdot\frac{7}{3}\)
=>\(\frac{84}{60}-\frac{80}{100}\cdot\frac{7}{3}\)
=>\(\frac{7}{5}-\frac{4}{5}\cdot\frac{7}{3}=\frac{7}{5}-\frac{28}{15}\)
=>\(\frac{7}{5}-\frac{18}{14}=\frac{98}{60}-\frac{90}{60}=\frac{8}{60}=\frac{4}{30}\)
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}.\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)
\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}\cdot\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)
\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)
\(A=1+\frac{1}{2}\)
\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)
\(A=\frac{3}{2}\)
a, \(\left(\dfrac{3}{8}+\dfrac{-3}{4}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\)
\(=\left(\dfrac{-3}{8}+\dfrac{7}{12}\right)\dfrac{5}{6}+\dfrac{1}{2}\)
\(=\dfrac{5}{24}.\dfrac{5}{6}+\dfrac{1}{2}\)
\(=\dfrac{25}{144}+\dfrac{1}{2}\)
\(=\dfrac{97}{144}\)
b, \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{5}\)
\(=\dfrac{28}{15}.0,75-\dfrac{4}{5}:\dfrac{7}{5}\)
\(=\dfrac{7}{5}-\dfrac{4}{7}\)
\(=\dfrac{29}{35}\)
\(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):1\dfrac{2}{5}\)
\(=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right):\dfrac{7}{5}\)
\(=\dfrac{7}{5}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right):\dfrac{7}{5}\)
\(=\dfrac{7}{5}-\dfrac{16}{20}:\dfrac{7}{5}=\dfrac{7}{5}-\dfrac{4}{5}.\dfrac{5}{7}=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49}{35}-\dfrac{20}{35}=\dfrac{29}{35}\)
\(A=\dfrac{9-18+14}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{5}{24}\cdot\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{1}{4}+\dfrac{1}{2}=\dfrac{3}{4}\)
\(B=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right)\cdot\dfrac{5}{7}\)
\(=\dfrac{7}{5}-\dfrac{11+5}{20}\cdot\dfrac{5}{7}\)
\(=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49-20}{35}=\dfrac{29}{35}\)
a:\(=5-\dfrac{7}{39}\cdot\dfrac{13}{7}+\dfrac{2}{9}=5-1+\dfrac{2}{9}=4+\dfrac{2}{9}=\dfrac{38}{9}\)
b: \(=\dfrac{28}{15}:\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right)\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{4}{5}\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{12}{35}=\dfrac{676}{315}\)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{11}{20}+25\%\right)\cdot\dfrac{7}{5}\)
\(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(0,55+0,25\right)\cdot\dfrac{7}{5}\)
\(=\dfrac{7}{5}-0,8\cdot\dfrac{7}{5}=\dfrac{7}{5}\cdot0,2=\dfrac{7}{5}\cdot\dfrac{1}{5}=\dfrac{7}{25}\)