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a: \(=\sqrt{\dfrac{25}{16}\cdot\dfrac{49}{9}\cdot\dfrac{1}{100}}=\dfrac{5}{4}\cdot\dfrac{7}{3}\cdot\dfrac{1}{10}=\dfrac{35}{120}=\dfrac{7}{24}\)
b: \(=\sqrt{1.44\cdot0.81}=1.2\cdot0.9=1.08\)
c: \(=\sqrt{\dfrac{\left(165-124\right)\left(165+124\right)}{164}}=\sqrt{\dfrac{1}{4}\cdot289}=\dfrac{17}{2}\)
d: \(=\sqrt{\dfrac{\left(149-76\right)\left(149+76\right)}{\left(457-384\right)\left(457+384\right)}}=\sqrt{\dfrac{225}{841}}=\dfrac{15}{29}\)
a) \(\sqrt{\frac{196}{169}}=\frac{14}{13}\)
b) \(\sqrt{2\frac{14}{25}}=\sqrt{\frac{64}{25}}=\frac{8}{5}\)
c) \(\sqrt{\frac{0,36}{25}}=\frac{0,6}{5}=\frac{3}{25}\)
d) \(\sqrt{\frac{6,4}{4,9}}=\sqrt{\frac{64}{49}}=\frac{8}{7}\)
a) \(\sqrt{\frac{196}{169}}=\sqrt{\left(\frac{14}{13}\right)^2}=\frac{14}{13}\)
b) \(\sqrt{2\frac{14}{25}}=\sqrt{\frac{64}{25}}=\sqrt{\left(\frac{8}{5}\right)^2}=\frac{8}{5}\)
c) \(\sqrt{\frac{0,36}{25}}=\sqrt{\left(\frac{0,6}{5}\right)^2}=\frac{0,6}{5}=\frac{6}{50}=\frac{3}{25}\)
d) \(\sqrt{\frac{6,4}{4,9}}=\sqrt{\frac{64}{49}}=\sqrt{\left(\frac{8}{7}\right)^2}=\frac{8}{7}\)
a) Ta có: \(\sqrt{45}:\sqrt{80}\)
\(=\sqrt{\frac{45}{80}}=\sqrt{\frac{9}{20}}\)
\(=\frac{3}{2\sqrt{5}}\)
b) Ta có: \(\sqrt{\frac{3}{15}}:\sqrt{\frac{36}{45}}\)
\(=\sqrt{\frac{1}{5}:\frac{4}{5}}\)
\(=\sqrt{\frac{1}{5}\cdot\frac{5}{4}}\)
\(=\sqrt{\frac{1}{4}}=\frac{1}{2}\)
c) Ta có: \(\sqrt{\frac{72}{9}}:\sqrt{8}\)
\(=\frac{\sqrt{8}}{\sqrt{8}}=1\)
d) Ta có: \(\sqrt{\frac{288}{169}}:\sqrt{\frac{8}{225}}\)
\(=\sqrt{\frac{288}{169}:\frac{8}{225}}\)
\(=\sqrt{\frac{288}{169}\cdot\frac{225}{8}}\)
\(=\sqrt{\frac{8100}{169}}=\frac{90}{13}\)
\(\sqrt{\frac{3,6}{4,9}}=\pm\frac{6}{7}\)
\(\sqrt{1,44\cdot1,21-1,44\cdot0,4}\)
\(=\sqrt{1,44\left(1,21-0,4\right)}\)
\(=\sqrt{1,44\cdot0,81}\)
\(=\sqrt{1,664}\)
\(=\sqrt{1,08}\)
c tự tính đi
a)\(\sqrt{\frac{3,6}{4,9}}=\pm\frac{6}{7}\)
b)\(\sqrt{1,44\cdot1,21-1,44\cdot0,4}=\sqrt{1,44\left(1,21-0,4\right)}\)
\(=\sqrt{1,44\cdot0,81}=1,2\cdot0,9=1,08\)