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\(1\frac{1}{3}\)x \(1\frac{1}{8}\)x \(1\frac{1}{15}\)x .......x \(1\frac{1}{99}\)= \(\frac{4}{3}\)x \(\frac{9}{8}\)x\(\frac{16}{15}\)x..........x \(\frac{100}{99}\)
=\(\frac{2.2}{1.3}\)x\(\frac{3.3}{2.4}\)x\(\frac{4.4}{3.5}\)x.......x \(\frac{10.10}{9.11}\)= \(\frac{2.3.4....10}{1.2.3.....9}\)x \(\frac{2.3.4....10}{3.4.5....11}\)
= \(\frac{10}{1}\)x\(\frac{2}{11}\)=\(\frac{20}{11}\)
4/3 x 9/8 x16/15 x ..... x 100/99
=2x2/1x3 x 3x3/2x4 x 4x4/3x5 x ... x 10x10/9x11
=2x3x4x....x10/1x2x3x..x9 x 2x3x4x...x10/3x4x5x...x11
=10 x 2/11=20/11
a) \(x+4\frac{1}{5}=5\frac{2}{3}\times10\frac{1}{2}\)
\(x+\frac{21}{5}=\frac{17}{3}\times\frac{21}{2}\)
\(x+\frac{21}{5}=\frac{119}{2}\)
\(x=\frac{119}{2}-\frac{21}{5}\)
\(x=\frac{553}{10}\)
b) \(\frac{24}{5}-x=2\frac{1}{4}:1\frac{3}{4}\)
\(\frac{24}{5}-x=\frac{9}{4}:\frac{7}{4}\)
\(\frac{24}{5}-x=\frac{9}{4}.\frac{4}{7}\)
\(\frac{24}{5}-x=\frac{9}{7}\)
\(x=\frac{24}{5}-\frac{9}{7}\)
\(x=\frac{123}{35}\)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(x\times2+3,5=24,25\)
\(x\times2=24,25-3,5\)
\(x\times2=20,75\)
\(x=20,75:2\)
\(x=10,375\)
Vậy \(x=10,375\)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(x.2+\frac{7}{2}=\frac{97}{4}\)
\(x.2=\frac{97}{4}-\frac{7}{2}\)
\(x.2=\frac{97}{4}-\frac{14}{4}\)
\(x.2=\frac{83}{4}\)
\(\Rightarrow x=\frac{83}{4}:2=\frac{83}{8}=10\frac{3}{8}\)
Vậy \(x=10\frac{3}{8}\)
Ủng hộ mk nha !!! ^_^
Tim x:
x X 12 + x X 14 + x X 18 = \(\frac{21}{24}\)
x X (\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\)) = \(\frac{21}{24}\)
x X (\(\frac{4}{8}+\frac{2}{8}+\frac{1}{8}\)) = \(\frac{21}{24}\)
x X \(\frac{9}{8}\)= \(\frac{21}{24}\)
x = \(\frac{21}{24}\): \(\frac{9}{8}\)
x = \(\frac{21}{24}\)X \(\frac{8}{9}\)
x = \(\frac{7}{9}\)
\(x\times\frac{1}{2}+x\times\frac{1}{4}+x\times\frac{1}{8}=\frac{21}{24}\)
\(\Rightarrow x\times\left[\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right]=\frac{21}{24}\)
\(\Rightarrow x\times\left[\frac{4+2+1}{8}\right]=\frac{21}{24}\)
\(\Rightarrow x\times\frac{7}{8}=\frac{21}{24}\)
\(\Rightarrow x\times\frac{7}{8}=\frac{7}{8}\)
\(\Rightarrow x=\frac{7}{8}:\frac{7}{8}=1\)
\(x+3\frac{1}{2}=24\frac{1}{4}-x\)
\(\Leftrightarrow x+x=24\frac{1}{4}-3\frac{1}{2}\)
\(\Leftrightarrow2x=\frac{94}{4}-\frac{14}{4}\)
\(\Leftrightarrow2x=\frac{90}{4}=\frac{45}{2}\)
\(\Leftrightarrow x=\frac{45}{2}:2\)
\(\Leftrightarrow x=\frac{45}{4}\)