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\(a,3^{-2}.9^n=3^n\)
\(\Leftrightarrow3^{-2}.3^{2n}=3^n\)
\(\Leftrightarrow3^{2n-2}=3^n\)
\(\Leftrightarrow2n-2=n\)
\(\Leftrightarrow n=2\)
\(b,\left(\frac{9}{25}\right)^n=\left(\frac{3}{5}\right)^{-4}\)
\(\Leftrightarrow\left(\frac{3}{5}\right)^{2n}=\left(\frac{3}{5}\right)^{-4}\)
\(\Leftrightarrow2n=-4\)
\(\Leftrightarrow n=-2\)
a)5-1*5n=125
5-1+n=53
=>-1+n=3
n=3+1
n=4
b)3-1*3n+6*3n-1=7*36
3n-1+6*3n-1=36*7
3n-1(1+6)=7*36
3n-1*7=7*36
=>n-1=6
n=6+1
n=7
c)34<1/9*27n<310
34<3-2*33n<310
34<33n-2<310
=>4<3n-2<10
6<3n<12
2<n<4
n=3
d)25<5n/5<625
52<5n-1<54
=>2<n-1<4
3<n<5
n=4
(nể tình bạn nên làm hết ln, nếu cậu k phải bn tớ thì tớ làm dc 2,3 câu xong tương tự r)
Câu 1:
a) 2225 và 3150
Ta có:2225=(29)25=51225
3150=(36)25=72925
Vì 51225<72925
Suy ra: 2225<3150
Câu 2:
a)\(25^3:5^2=\left(5^2\right)^3:5^2=5^6:5^2=5^4\)
b)\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
c)\(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2=3+\frac{1}{4}:2=3+\frac{1}{8}=\frac{25}{8}\)
Câu 3:
a)\(9.3^3.\frac{1}{81}.3^2=3^2.3^3.3^2.\left(\frac{1}{3^4}\right)=3^7:3^4=3^3\)
b)\(4.2^5:\left(2^3.\frac{1}{16}\right)=2^2.2^5:\left(2^3.\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^8\)
c)\(3^2.2^5.\left(\frac{2}{3}\right)^2=288.\frac{4}{9}=2^7\)
d)\(\left(\frac{1}{3}\right)^3.\frac{1}{3}.9^2=\left(\frac{1}{3}\right)^4.\left(3^2\right)^2=3^4.\left(\frac{1}{3}\right)^4=3^4:3^4=1\)
C.\(\frac{4^5.\left(1+1+1+1\right)}{3^5.\left(1+1+1\right)}.\frac{6^6}{2^{5+}2^5}=\frac{4^6}{3^6}.\frac{6^6}{2^5+2^5}=\frac{24^6}{3^6.\left(2^5+2^5\right)}=\frac{8^6}{2^5.\left(1+1\right)}\)=\(\frac{8^6}{2^6}\)=4^6=4096
a) \(3^{-2}\cdot9^n=3^n\)
\(\Rightarrow3^{-2}\cdot3^{2n}=3^n\)
\(\Rightarrow3^{2n-2}=3^n\Rightarrow2n-2=n\)
\(\Rightarrow2n-n=2\)
=> n = 2
Vậy n = 2
b) \(\left(\dfrac{9}{25}\right)^n=\left(\dfrac{3}{5}\right)^{-4}\)
=> \(\left(\dfrac{3}{5}\right)^{2n}=\left(\dfrac{3}{5}\right)^{-4}\)
=> 2n = -4
=> n = -2
Vậy n = -2
1,
a) 3-2 . 9n = 3n
(=) 3-2 . ( 32 )n = 3n
(=) 3-2 . 3^2n = 3n
(=) 3^ -2+2n = 3n
=> n = -2 + 2n
(=) n - 2n = -2
=> -n = -2
=> n = 2
Vậy n = 2
b) ( 9/25 )n = ( 3/5 )-4
(=) [ ( 3/5 )2]n = ( 3/5 )-4
(=) ( 3/5 )^2n = ( 3/5 )-4
(=) 2n = -4
=> n = -2
Vậy n = -2