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\(1-\left(5\frac{5}{36}+y-7\frac{7}{18}\right):15\frac{3}{4}=0\)
=>\(1-\left(\frac{185}{36}+y-\frac{133}{18}\right):\frac{63}{4}=0\)
=>\(1-\left(-\frac{9}{4}+y\right).\frac{4}{63}=0\)
=>\(1-\left(-\frac{1}{7}+\frac{4}{63}y\right)=0\)
=>\(1+\frac{1}{7}-\frac{4}{63}y=0\)
=>\(\frac{8}{7}-\frac{4}{63}y=0\)
=>\(63.\frac{8}{7}-63.\frac{4}{63}y=63.0\)
=>\(72-4y=0\)
=>\(4y=72-0\)
=>\(4y=72\)
=>\(y=72:4\)
=>\(y=18\)
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( 2 x y + 2/15 ) x 3 = 4/5
( 2 x y + 2/15 ) = 4/5 : 3
( 2 x y + 2/15 ) = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 :2
y = 1/15
(2 x y + 2/15) x 3 = 4/5
2 x y + 2/15) = 4/5 : 3
2 x y + 2/15 = 4/15
2 x y = 4/15 - 2/15
2 x y = 2/15
y = 2/15 : 2
y = 1/15
7/9 x (2 - 1/3 x y) = 14/15
(2 - 1/3 x y) = 14/15 : 7/9
(2 - 1/3 x y) = 6/5
2 - y = 6/5 x 1/3
2 - y = 2/5
y = 2/5 + 2
y = 12/5
4/21 + 5 x y - 8/7 = 1/3
4/21 + 5 x y = 1/3 + 8/7
4/21 + 5 x y = 31/21
5 x y = 31/21 - 4/21
5 x y = 9/7
y = 9/7 : 5
y = 9/35
7/12 x y - 3/12 x y = 5
y x (7/12 - 3/12) = 5
y x 1/3 = 5
y = 5 : 1/3
y = 15
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1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
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a, 75 - 5 . ( 15 - 10 ) - ( -60 ) = 75 - 5 . 5 + 60 = 135 - 25 = 110
b, 136 - ( -7 ) + 6 - 23 - 36 = 136 + 7 + 6 - 23 - 36 = ( 136 - 36 ) + ( 7 + 6 - 23 ) = 100 - 10 = 90
c, ( -15 - 17 ) . ( -15 + 7 ) = -32 . ( -8 ) = 256
d, ( -9 - 18 ) : ( -9 ) = -27 : ( -9 ) = 3
Bài 2:
a, 2x - 17 = ( -3x - 18 )
<=> 2x + 3x = 17 - 18
<=> 5x = -1
<=> x = -1/5
b, ( 13 - IxI ) + 15 = 20
<=> 13 - |x| = 5
<=> |x| = 8
<=> x = 8 hoặc x = -8
c, Ix + 5I - ( x + 5 ) = 0
<=> |x + 5| = x + 5
Đk: x + 5 ≥ 0 => x ≥ -5
\(\Leftrightarrow\orbr{\begin{cases}x+5=x+5\\x+5=-x-5\end{cases}\Leftrightarrow}\orbr{\begin{cases}0x=0\\2x=-10\end{cases}\Leftrightarrow}\orbr{\begin{cases}x\ge-5\\x=-5\end{cases}}\)
Vậy x ≥ -5
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a,\(\frac{-\chi}{4}=\frac{-9}{\chi}\Rightarrow-\chi.\chi=4.\left(-9\right)\)
\(\Rightarrow-2\chi=-36\Rightarrow\chi=-36:\left(-2\right)\)
\(\Rightarrow\chi=18\)
tìm y hay sao bạn
\(1-\left[5\frac{5}{36}+y-7\frac{7}{18}\right]=0\)
\(1-\left[\left(5\frac{5}{36}-7\frac{7}{18}\right)+y\right]=0\)
\(1-\left[\left(5\frac{5}{36}-7\frac{14}{36}\right)+y\right]=0\)
\(1-\left[2\frac{-1}{4}+y\right]=0\)
\(1-\frac{-9}{4}+y=0\)
\(\left(1+\frac{9}{4}\right)+y=0\)
\(\frac{13}{4}+y=0\)
\(y=0-\frac{13}{4}\)
\(y=\frac{-13}{4}\)