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2+3/4=11/4 ; 2-3/5=7/5
5/7:6=5/42 ; 5+2/7=37/7
Bài 2: a) x-1/6=1/2+1/3
x-1/6=5/6
x=5/6+1/6
x=1
b) x+1/8=1/2-1/3
x+1/8=1/6
x=1/6-1/8
x=1/24
c) x:1/2=2/3.3/4
x:1/2=1/2
x=1/2.1/2
x =1/4
a) \(x.\frac{3}{4}=\frac{4}{5}.2\)
\(x.\frac{3}{4}=\frac{8}{5}\)
\(x=\frac{8}{5}:\frac{3}{4}=\frac{32}{15}\)
b) \(x:1\frac{1}{7}=2\frac{2}{3}\)
\(x:\frac{8}{7}=\frac{8}{3}\)
\(x=\frac{8}{3}.\frac{8}{7}=\frac{64}{21}\)
c) \(x-1\frac{2}{5}=4\frac{1}{6}-2\frac{2}{3}\)
\(x-\frac{7}{5}=\frac{25}{6}-\frac{8}{3}=\frac{3}{2}\)
\(x=\frac{3}{2}+\frac{7}{5}=\frac{29}{10}\)
d) \(2\frac{2}{3}+x:\frac{3}{2}=2\frac{1}{3}\)
\(\frac{8}{3}+x:\frac{3}{2}=\frac{7}{3}\)vô lí vì 8/3 lớn hơn 7/3
(1+1/2)(1+1/3)...(1+1/99)
=(3/2)(4/3)(5/4)...(100/99)
=100/2=50
sorry tui làm sai câu này!!!
2/3 +4/37 +5/111 +260 /1443
=962/1443+156/1443+65/1443+260/1443
= 962+156+65+260/1443=1
tìm x
1)1/2 - ( x+3/14) = 1/6
=> x+3/14=1/2-1/6
=> x= 1/3 - 3/14
=> x= 5/42
2)( x- 1/3 ) -5/2 = 1/7
=> x-1/3= 1/7+5/2
=> x= 37/14+1/3
=> x= 125/42
3)5/8 + ( x- 1/4 ) = 4/3
=>x-1/4=4/3-5/8
=>x= 17/24 +1/4
=> x= 23/24
4) 4/3 - ( 1/4 -x ) =1
=>1/4-x=4/3-1
=>x=1/4-1/3
=> x= -1/12
Chúc bạn Hk tốt!!!
2/3 +4/37 +5/111 +260 /1443\(=\frac{635}{629}\)
Tìm x
1. \(x=\frac{5}{42}\)
2. \(x=\frac{125}{42}\)
3. \(x=\frac{23}{24}\)
4. \(x=-\frac{1}{12}\)
Chúc bạn Hk tốt!!!
c,Dãy trên có số số hạng là:
(52-2):2+1=26 số hạng
Tổng của dãy trên là:
(52+2).26:2=702
Đáp số :.....
(1-1/2) x (1-1/3) x .... x (1-1/100)
= 1/2 x 2/3 x ... x 99/100
= 1x2x...x99/2x3x..x100
= 1/ 100
a, \(\frac{3}{5}+25-\frac{1}{5}\)
\(=\left(\frac{3}{5}-\frac{1}{5}\right)+25\)
\(=\frac{2}{5}+25\)
\(=25\frac{2}{5}\)
\(=25,4\)
b, \(13.3.32,27+67,63.39\)
\(=39.32,27+67,63.39\)
\(=39\left(32,37+67,63\right)\)
\(=39.100\)
\(=3900\)
c, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)....\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{99}{100}\)
\(=\frac{1}{100}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)\times\left(1-\dfrac{1}{6}\right)\times...\times\left(1-\dfrac{1}{100}\right)\\ =\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\times\dfrac{5}{6}\times...\times\dfrac{99}{100}\\ =\dfrac{1\times2\times3\times4\times5\times...\times99}{2\times3\times4\times5\times6\times...\times100}\\ =\dfrac{1}{100}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times...\times\left(1-\dfrac{1}{100}\right)\)
\(=\dfrac{1}{2}\times\dfrac{2}{3}\times...\times\dfrac{99}{100}\)
\(=\dfrac{1}{100}\)