Question

[Nguyễn Hải Yến]

(1-1/2)*(1-1/3)*(1-1/4)*(1-1/5)*.........*(1-1/2011)*(1-2012)

Answer 1

[Trần Thanh Phương]

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{2012}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot...\cdot\frac{2011}{2012}\)

\(=\frac{1\cdot2\cdot...\cdot2011}{2\cdot3\cdot...\cdot2012}\)

\(=\frac{1}{2012}\)

Answer 2

[Không Tên]

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2011}\right)\left(1-\frac{1}{2012}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{2010}{2011}.\frac{2011}{2012}\)

\(=\frac{1.2.3...2010.2011}{2.3.4...2011.2012}\)

\(=\frac{1}{2012}\)