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Tìm X
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\)
\(=\frac{1}{5}\)
\(\Rightarrow x-100=\frac{1}{5}\)
\(x=\frac{1}{5}+100\)
\(x=\frac{1}{5}+\frac{500}{5}\)
\(x=\frac{501}{5}\)
<=> x : ( 1/2+1/4+1/8) x 100 = 13.25
<=> x : ( 4/8 + 2/8 + 1/8) = 13.25 : 100
<=> x : 7/8 = 0,1325
<=> x = 0,1325 x 7/8
<=> x= 0.1159375
Chả biết đúng không nữa nhưng hình như là sai ế :)
x:1/2+x:1/4+x:25/2=13,25
x:(1/2+1/4+25/2)=13,25
x:53/4=13,25
x:53/4=53/4
x=53/4x53/4
x=2809/16
\(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right)....\left(1-\frac{1}{99}\right)\)
\(=\frac{1}{2}.\frac{2}{3}....\frac{98}{99}=\frac{1.2....98}{2.3...99}=\frac{1}{99}\)
(1+1/2)x(1+1/3)x(1+1/4)x....x(1+1/98)x(1+1/99)
=3/2x4/3x5/4x..........x99/98x100/99
=(3x4x5x........x99x100)/2x3x4x........x98x99
Giản ước ta được:
=100/2
=50
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{99}\right)\times\left(1-\dfrac{1}{100}\right)\)
\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{98}{99}\times\dfrac{99}{100}\)
\(=\dfrac{1\times2\times3\times...\times98\times99}{2\times3\times4\times...\times99\times100}=\dfrac{1}{100}\)
(1 - 1/2) × (1 - 1/3) × (1 - 1/4) × ... × (1 - 1/99) × (1 - 1/100)
= 1/2 × 2/3 × 3/4 × ... × 98/99 × 99/100
= 1/100
X : 1/2 + X : 1/4 + X : 1/8 x 100 = 13,25
Xx3 + (1/2+1/4+1/8) =13,25: 100
Xx3 + 7/8 = 0,1325
Xx3= 0,1325 -7/8
Xx3= -- 0,7425
X= --0,7425 : 3
X= --0,2475
nhé bạn
X : 1/2 + X : 1/4 + X : 1/8 x 100 = 13,25
Xx3 + (1/2+1/4+1/8) =13,25: 100
Xx3 + 7/8 = 0,1325
Xx3= 0,1325 -7/8
Xx3= -- 0,7425
X= --0,7425 : 3
X= --0,2475
Ai k mk mk k lại!