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\(a,\sqrt{4,9.360}=\sqrt{49.36}=\sqrt{49}.\sqrt{36}=7.6=42\)
b,\(\sqrt{2,25.0,04}=\sqrt{0.09}=0.3\)
c, \(\sqrt{3\dfrac{1}{16}.2\dfrac{4}{15}}=\sqrt{\dfrac{49}{16}.\dfrac{44}{15}}=\sqrt{\dfrac{49}{16}}.\sqrt{\dfrac{44}{15}}=\dfrac{7}{4}.1,7=2,99\approx3\)
e, \(\sqrt{\dfrac{144}{169}}=\dfrac{\sqrt{144}}{\sqrt{169}}=\dfrac{12}{13}\)
g,\(\dfrac{\sqrt{27}}{\sqrt{3}}=\sqrt{\dfrac{27}{3}}=\sqrt{9}=3\)
f,\(\sqrt{2,25}=\dfrac{3}{2}\)
n,\(\sqrt{\dfrac{25}{529}}=\dfrac{\sqrt{25}}{\sqrt{529}}=\dfrac{5}{23}\)
\(\text{a) }\sqrt{6+2\sqrt{5}}+\sqrt{6-2\sqrt{5}}\\ =\sqrt{5+1+2\sqrt{5}}+\sqrt{5+1-2\sqrt{5}}\\ =\sqrt{\left(\sqrt{5}+1\right)^2}+\sqrt{\left(\sqrt{5}-1\right)^2}\\ =\sqrt{5}+1+\sqrt{5}-1\\ =2\sqrt{5}\)
\(\text{b) }\sqrt{5+2\sqrt{6}}+\sqrt{5-2\sqrt{6}}\\ =\sqrt{3+2+2\sqrt{6}}+\sqrt{3+2-2\sqrt{6}}\\ =\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}+\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\\ =\sqrt{3}+\sqrt{2}+\sqrt{3}-\sqrt{2}\\ =2\sqrt{3}\)
\(\text{c) }\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}\\ =\sqrt{7+1-2\sqrt{7}}-\sqrt{7+1+2\sqrt{7}}\\ =\sqrt{\left(\sqrt{7}-1\right)^2}-\sqrt{\left(\sqrt{7}+1\right)^2}\\ =\sqrt{7}-1-\sqrt{7}-1\\ =-2\)
\(\text{d) }\sqrt{29+12\sqrt{5}}+\sqrt{29-12\sqrt{5}}\\ =\sqrt{20+9+12\sqrt{5}}+\sqrt{20+9-12\sqrt{5}}\\ =\sqrt{\left(\sqrt{20}+3\right)^2}+\sqrt{\left(\sqrt{20}-3\right)^2}\\ =\sqrt{20}+3+\sqrt{20}-3\\ =2\sqrt{20}\\ =4\sqrt{5}\)
\(\text{e) }\left(\sqrt{0,25}-\sqrt{225}+\sqrt{2,25}\right):\sqrt{169}\\ =\left(0,5-15+1,5\right):13\\ =\left(-13\right):13=-1\)
\(\text{f) }3-\sqrt{5}+3+\sqrt{5}\\ =6\)
Câu 2:
Ta có: \(9-7x^2=30\)
\(\Leftrightarrow7x^2=9-30=-21\)(Vô lý)
(\(\sqrt{0,25}\) - \(\sqrt{\left(-15\right)^2}\) + \(\sqrt{2,25}\)) : \(\sqrt{169}\)
= (\(\sqrt{\left(0,5\right)^2}\) - \(\sqrt{\left(15\right)^2}\) + \(\sqrt{\left(1,5\right)^2}\)): \(\sqrt{\left(13\right)^2}\)
= (0,5 - 15 + 1,5): 13
= (2 - 15): 13
= -13 : 13
= -1